... ( xo ) 4 ( xo ) + } F ( xo ) 4 ′ ( x ) + F ' ( x , ) q ′ ( x ' , ) + ... + F ′ ( 2 , -1 ) 4 ′ ( p - 1 ) - [ { B h B , d3 h3 + dx 4 ! " da3 - - 1⁄2 ( x1 ) x = xp ... · } F ( x ) 4 ′ ( x ) ( 5 ) = ¦ F ( xo ) ...
... Xo 8 = 4 : d3 Z ' p da3 Xo S = = 5 : hp ho b 3 [ 2 ] = ( - ( 43 ) + 1 ) +12 ( 6 ) 2-4 % ) -- bs hp As hp hp -36 ( b + a - 24 . ) N. 3 Xp ( bs Xp2 hp 3 ( b1 hp hp [ d ] - ( - ( 4 ) + a2 ) + 20 ( 6 , - a . ) - 120 ( 6.7+ a ) Z ...
... xo + xo ' ; ( 20 ) Ex 。= xo ' . By ( 10 ) , as applied to both component sources and their combination , we have p ' ( x ' ) = ' ( § ' + xo ' ) = 4 ' ( § ' ) , - - · $ ( x − x ' ) = $ ( § — § ' + x − xo ' ) = 4 ( § — § ' — xo ' ) , φ ...
... xo ' ; so that ( 20 ) Ex 。= xo ' . By ( 10 ) , as applied to both component sources and their combination , we have ' ( x ) = ' ( § + xo ' ) = 4 ' ( § ' ) , • ( x − x ' ) = $ ( § — § ' + xo — xo ' ) = 4 ( § — § ' — xo ' ′ ) , - • ( x ) + ...
... Xo , 4 2 CSQ Xp , 4 2 CSQ Xo , F 2 CSQ XP , F 2 CSQ Xo , M 2 CSQ XP , M 2 CSQ Xo , R 2 CSQ XP , R 2 CSQ X , 34 Xo , 34 2 CSQ Xp , 34 MISC k ( m¿ ) 1/3 2 SCNFF hoa , hob 150 THI 0 150 THI Ꮎ Dimension COMMON block 13 PTI 2 SCNFF 2 SCNFF ...